- tionless pulley as shown in the gure below. The object of mass m 1 = 6.60 kg is released from rest at a height h = 3.40 m above the table. • a)Using the isolated system model, determine the speed of the object of mass m 2 = 3.00 kg just as the 6.60kg object hits the table. • b)Find the maximum height above the table to which the 3.00kg ...
- Determine its acceleration if the mass of the crate is 70 kg. T mg = ma i.e = 70 a from which, acceleration, a = = m/s 4. A ship is travelling at that both masses hang vertically downwards and are at the same height. When the system is released, find (a) the acceleration of the system, and (b) the...
- The total mass of the rocket and its full load of fuel is {eq}2.8 \times 10^6 {/eq} kg. The constant force provided by the rocket's motors is {eq}3.2 \times 10^7 {/eq} N. Calculate the vertical ...
- Find the angular acceleration of the sphere when it reaches at the bottom of the incline. Take mass of the sphere is 2 kg and radius of the sphere is 10 cm.
- During the car's fall, there is no slipping between the (massless) rope, the pulley, and the winch drum. The moment of inertia of the winch drum is 344 kg.m2 and that of the pulley is 3 kg.m2 The radius of the winch drum is 0.80 m and that of the pulley is 0.30 m. Find the speed of the car as m/s it hits the water. MQM)tmls 2nd —Tl Wench drum
- A force of 3.0 N and 1.0 N act on a 6.0 kg mass as shown. What is the acceleration of the 6.0 kg mass? here is my solution . a^2 + b^2 = c^2. 1^2 +3^2 = c^2
- 34. A speed boat in the water experiences an acceleration of 0.524 m/s2. The boat's mass is 842 kg. What is the force that the boat's engine's are putting out? 35. A stalled car is pushed with a force of 342 N from rest. How far does the car travel in 12 seconds is it's mass is 989 kg? 36.
- The mass of the moon is 7.35 x 10 22 kg. Find the acceleration due to gravity on the surface of the moon. Answer: On the surface of the moon, the distance to the center of mass is the same as the radius: r = 1.74 x 10 6 m = 1 740 000 m. The acceleration due to gravity on the surface of the moon can be found using the formula: g = 1.620 m/s 2
- 5) A 10.0 kg block lies on a frictionless horizontal table. To the right of the block is a frictionless pulley. A 25.0 kg mass is hanging off the table connected to the 10.0 kg mass and pulley via some string. a) Find the acceleration of the system. b) Find the tension in the string. b) T = mg - ma T = 25 kg (9.81 ms-2) – 25kg(7.01ms-2) T ...
- 3 2010 Question 12 (a) [Ordinary Level] (i) A cyclist on a bike has a combined mass of 120 kg. The cyclist starts from rest and by pedalling applies a net force of 60 N to move the bike along a horizontal road. Calculate the acceleration of the cyclist (i) Calculate the maximum velocity of the cyclist after 15 seconds.
Let us apply Newton's second law to the block. The mass of the block is , and its acceleration is zero, since the block is assumed to be in equilibrium.The block is subject to two forces, a downward force due to gravity, and an upward force due to the tension of the string.
- Acceleration = (force)/(mass)For the first object, A = 20/10 = 2 m/s2For the second object, A = 30/18 = 12/3 m/s2The acceleration of the first object is 20% greaterthan the acceleration of the ...
- field space around a mass in which another mass will experience a force gravitational force the Like any other force, tension can accelerate or contribute to the acceleration of an object or system We can find the tension in each of the three ropes by finding the vector sum of the tensions and setting...
- Oct 27, 2008 · Calculate the acceleration due to gravity on Mercury. The radius of Mercury is about 2.43 x 106 m and its mass is 3.18 x 1023 kg.
- If the mass of the object is 2.00 kg and acceleration experienced by the object is 2.00 ms-2, then determine the magnitude and direction of force act by Tom. A. 1.70 N and its direction is opposite with force acted by Andre.w
- F = ma = 820 kg × 9.1 = 7500 N w m s F = mg F 210 N m = = = 21 kg g 9.8 To calculate force, first find acceleration. To calculate force, first find mass from weight. zero N – uld be 210 N, which makes a net force of zero 2 m net s F = ma = 21 kg × 1.5 = 32 N 1.0 kg? kg = 130 lbs × = 59 kg 2.2 lbs w s2 F = mg = 59 kg × 9.8 = 580 N m = 5.0 g
- To calculate weight, we use Newton's 2nd Law of Motion, which gives us the formula "Force = mass x acceleration". We would take the mass given, 80 kg, and multiply it times the acceleration of ...
- Calculate the acceleration using the procedure as in C-2. Record. 2. Add 1 kg and repeat procedure 1. Add 2 kg and repeat procedure 1. Also repeat for 3 kg, 4 kg, and 5 kg. Mass the cart in kg. 3. For each ticker tape pulled, 1 kg, 2 kg, 3 kg, 4 kg, 5 kg added to the cart, calculate the acceleration of the cart.
- (a) The acceleration (which equals F/m in this problem) is the derivative of the velocity. Thus, the velocity is the inte gral of F/m, so we find the “area” in the graph (15 units) and divide by the mass (3) to obtain v – v o = 15/3 = 5. Since vSince v o = 3.0 m/s, then3.0 m/s, then
- 2. Only two forces act on an object (m = 4.00 kg): 60.0 N in the +y direction and 40.0 N in the +x direction. Find the magnitude and direction (relative to the x axis) of the acceleration of the object. 2(Cutnell 4.63) 18 m/s at 56.3° 3. A falling skydiver has a mass of 110 kg.
- Jan 05, 2014 · 7. A rope is tied to a ceiling and a light fixture of mass 12 kg is supported by it. What is the tension force in the rope? 8. What is the kinetic frictional force on an object of mass 37 kg as it moves over a surface where μ k = 0.22? 9. Does a couch of mass 150 kg move on a carpeted floor with μ s = 0.33 and μ k = 0.22, if it is pushed ...
A block of mass 2.21753 kg lies on a friction- less table, pulled by another mass 3.08244 kg under the influence of Earth’s gravity. The acceleration of gravity is 9.8 m/s2 . What is the magnitude of the net external force F acting on the two mass system connected by the string? Answer in units of N.
- A ball of mass 0.3 kg is attached to a string and is being spun in a circle (uniform circular motion). The tension of the string attached to the ball is 4.5N.
- Mar 20, 2017 · By Newton’s second law, [math]F = ma[/math] So given your values, [math]F = 2 \text{ kg} \times 4 \text{ m/s²} = 8 \text{ N}[/math] There is a net force of 8 newtons on this object.
- b. find the force of contact if the F is applied to m2 rather than m1. c. why are a. and b. not the same? 1. The total external force, F_ext, on the system is 3.2 N. The acceleration is : F_ext = Sum(m) * a 3.2 N / (2.3 kg + 1.2 kg) = a a = 0.91 The acceleration and masses haven't changed...
- 1. Mass on a spring. The force exerted by a spring when it is stretched a distance x from its equilibrium position The position, velocity and acceleration of the mass on the spring are given by Does the amplitude drastically effect the period? Find the percent error between the average of the measured...
- Newton's Second Law of Motion states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object. Newton's Second Law formula: F = m * a Where: F: the magnitude of the net force, in N
- Two blocks, one of mass m1= kg and the other of mass m2= kg both on inclined surfaces shown. The angle of the left incline is \theta 1 = degrees. And other other angle is \theta 2 = degrees. Find the tension, T, in the rope that connects the blocks through the frictionless pulley, and the acceleration, a, of the blocks.
- 3 2010 Question 12 (a) [Ordinary Level] (i) A cyclist on a bike has a combined mass of 120 kg. The cyclist starts from rest and by pedalling applies a net force of 60 N to move the bike along a horizontal road. Calculate the acceleration of the cyclist (i) Calculate the maximum velocity of the cyclist after 15 seconds.
By adding the equations, we find the acceleration: a = (m 2 – m 1)g/(m 1 + m 2) = (3.2 kg – 2.2 kg)(9.80 m/s2)/(3.2 kg + 2.2 kg) = 1.81 m/s2 for both blocks. For the motion of block 1 we take the origin at the ground and up positive. Until block 2 hits the ground, we have v 1 2 = v 01 2 + 2a(y 1 – y 01) = 0 + 2(1.81 m/s2) (3.60 m – 1.80 m), which gives v 1
- The coefficientof kinetic friction between the 4.00-kg block and the plane is0.25; that between the 8.00-kg block and the plane is 0.35. a) Calculate the acceleration of each block b) Calculate the tension in the string
- Hence from equation 23 it is clear that the centre of mass of the system of particles moves a if the whole mass of the system were concentrated at it. This result holds whether the system is a rigid body with particles in fixed position or system of particles with internal motions. Watch this tutorial for...
- Gdje kupiti Mass Acceleration - 3 kg - usporedi cijene, pogledaj značajke i izaberi trgovinu. Iako se podaci osvježavaju nekoliko puta dnevno savjetujemo da se prije kupovine detaljnije informirate direktno kod trgovine koju ste odabrali za kupnju proizvoda Mass Acceleration - 3 kg.
- 5) A block of wood of mass 40 kg is acted upon by a constant force of 12 N. How fast will the block be moving after three seconds? 6) The acceleration due to gravity on planet Barf is 3.5 times what it is on planet Earth. Thus an object of mass 22 kg on Earth would have what mass on planet Barf?
Feb 19, 2016 · The Moon and Earth rotate about their common center of mass, which is located about R CM = 4700 km from the center of Earth. (This is 1690 km below the surface.) Take the distance from the center of the earth to the center of the moon to be 3.84x10 8 m, and the mass of the moon to be 7.35x10 22 kg.
- There are 60 m of cable having a mass of 0.65 kg per meter of length wound on the reel at a radius of 375 mm. The empty spool has a mass of 28 kg and has a radius of gyration about its axis of 300 mm. A tension T of 90 Ν is required to overcome frictional resistance to turning. Calculate the angular acceleration α of the reel if a tension of
- 34. A speed boat in the water experiences an acceleration of 0.524 m/s2. The boat's mass is 842 kg. What is the force that the boat's engine's are putting out? 35. A stalled car is pushed with a force of 342 N from rest. How far does the car travel in 12 seconds is it's mass is 989 kg? 36.
- 2.60 s. Find the spring’s force constant. 13.7. When a body of unknown mass is attached to an ideal spring with force constant 120 N/m. it is found to vibrate with a fre quency of 6.00 Hz. Find (a) the period of themotion; (b) angu lar frequency; (c) the mass of thebody. 13.8. When a 0.750-kg mass oscillates on an ideal spring, the fre quency ...
- A 1.00 kg glider attached to a spring with a force constant of 25.0 N/m oscillates on a horizontal Problem 12.15. A block of unknown mass is attached to a spring with a spring constant of 6.50 N/m Find (f ) the speed and (g) the acceleration of the object when its position is equal to one third of the...
- 5) A block of wood of mass 40 kg is acted upon by a constant force of 12 N. How fast will the block be moving after three seconds? 6) The acceleration due to gravity on planet Barf is 3.5 times what it is on planet Earth. Thus an object of mass 22 kg on Earth would have what mass on planet Barf?
- The planet Krypton has a mass of 8.4 x 1023 kg andradius of 3.4 x 106 m.What is the acceleration of an object in free fall near thesurface of Krypton? the gravitational constant is 6.6726 x10-11 N x m2 / kg2. Ans. in unitsof m/s2.
Solved: The same force that gives the standard 1 kg mass an acceleration of 1.00\\ \\rm{m/s^2} acts first on body A, producing an acceleration of...
- Two blocks, one of mass m1= kg and the other of mass m2= kg both on inclined surfaces shown. The angle of the left incline is \theta 1 = degrees. And other other angle is \theta 2 = degrees. Find the tension, T, in the rope that connects the blocks through the frictionless pulley, and the acceleration, a, of the blocks.
- (a) The acceleration (which equals F/m in this problem) is the derivative of the velocity. Thus, the velocity is the inte gral of F/m, so we find the “area” in the graph (15 units) and divide by the mass (3) to obtain v – v o = 15/3 = 5. Since vSince v o = 3.0 m/s, then3.0 m/s, then
- Sep 08, 2011 · I am not sure what you're doing in multiplying 0.4 kg by 0.2 kg. First of all, that's not dimensionally consistent: (0.4 kg)*(0.2 kg) = (0.08 kg 2 ), which does not have units of mass. Second, there's no reason why the mass of object 2 is related to the mass of object 1.
- the bobsled. The mass of the bobsled is 390 kg. Calculate the acceleration of the bobsled. T/I [ans: 1.6 m/s2 [forward]] Sample Problem 3: Calculating Net Force and Acceleration Using an FBD A 9100 kg jet moving slowly on the ground fires its engines, resulting in a force of 22 000 N [E] on the jet. The force of friction on the jet is 3800 N [W].
- Find the acceleration w of body 2 in the arrangement shown in figure above, if its mass is η times as great as the mass of bar 1 and the angle that the inclined plane forms with the horizontal is equal to α.The masses of the pulleys and the threads, as well as the friction, are assumed to be negligible. Look into possible cases.
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- If we know the mass of an object in kilograms, and we know the acceleration that an object experiences then we can calculate the force exerted on that object by multiplying the _____ x _____. 1. An unbalanced force of 25 N in an Easterly direction is applied to a 12 kg mass. What will be the acceleration of the mass? 2.

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1. What is the weight of a 3.4 kg mass? F = ma Weight = force F = 3.4 x 9.8 = 33.32 N . 2. What mass has a weight of 720 N? F = ma 720 = m x 9.8 m = 720/9.8 m = 73.5kg. Go to Table of Contents. 3. Bob must exert 240 N of force on a 980 Kg car to move it at a constant speed up an incline. To find the acceleration, simply divide the force by the mass of the object being accelerated. Force is directly proportional to the acceleration, meaning that a greater force will lead to a greater acceleration. Mass is inversely proportional to acceleration, meaning that with a greater mass, the acceleration will decrease. 5

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Mass is the total amount of matter in an object, measured in kilograms (kg). Force is the push or pull on an object, measured in newton (N). Acceleration is the rate of change in velocity experienced by an object, measured in meter per second squared (m/s2). The second law of Newton pioneered the equation to calculate acceleration.3. What is the acceleration of a 10 kg mass pushed by a 5 N force? a = F/m = 5/10 = 0.5 m/sec^2. 4. Given a force of 88 N and an acceleration of 4 m/s2, what is the mass? m = F/a = 88/4 = 22 kg. 5. How much force is required to accelerate a 12 kg mass at 5 m/s2? F = m*a = 12*5 = 60 N. 6. Given a force of 10 N and an acceleration of 5 m/s2, what ...

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Aug 05, 2017 · We're asked to find the acceleration of a crate along a floor, given the coefficient of kinetic friction, the mass, and the applied force. The horizontal forces acting on the crate are. applied pushing force (directed in the positive direction) retarding friction force #f_k# (directed in the negative direction) The equation for the net ... Block 1 has a mass of 8 kg and block 2 has a mass of 12 kg. The coefficient of static friction between block 1 and block 2 is μs=0.4. The coefficient of kinetic friction between block 2 and the ground is μk=0.2. A person pulls horizontally on block 2 with a rope as shown in the figure.

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Online converter for units of acceleration. Meters per second squared, miles per second squared, car acceleration in seconds from zero to 60 mph? Click the Convert button. Your value gets instantly converted to all other units on the page. 3. Now find the unit you want and get the conversion result...

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Dec 09, 2012 · (a) Determine the acceleration of the 5.0-kg mass along the ramp. (Provide free-body diagrams for both masses.) (b) Determine the tension in the rope during the acceleration of the 5.0-kg mass along the ramp. (c) Determine the speed of projection of the 5.0-kg mass from the top of the ramp. The constant of gravity is known to be G = 6.67 x 10-11 m 3 /(s kg) and the mass of the earth is known to be m e = 5.98 x 10 24 kg. The measured period of the moon is 27.3 days (2.3 x 10 6 s). The distance between the moon and the earth can therefore be calculated: r = 3.82 x 10 8 m The planet Krypton has a mass of 8.4 x 1023 kg andradius of 3.4 x 106 m.What is the acceleration of an object in free fall near thesurface of Krypton? the gravitational constant is 6.6726 x10-11 N x m2 / kg2. Ans. in unitsof m/s2.

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16. The tension in the string shown is 12 N. Find the acceleration of mass m 1. m 2 m 1 = 4.0 kg A. 3.0 m/s2 B. 6.4 m/s2 C. 6.8 m/s2 D. 13 m/s2 17. A 75 kg man stands on a scale while accelerating upwards in an elevator. b. find the force of contact if the F is applied to m2 rather than m1. c. why are a. and b. not the same? 1. The total external force, F_ext, on the system is 3.2 N. The acceleration is : F_ext = Sum(m) * a 3.2 N / (2.3 kg + 1.2 kg) = a a = 0.91 The acceleration and masses haven't changed...b. find the force of contact if the F is applied to m2 rather than m1. c. why are a. and b. not the same? 1. The total external force, F_ext, on the system is 3.2 N. The acceleration is : F_ext = Sum(m) * a 3.2 N / (2.3 kg + 1.2 kg) = a a = 0.91 The acceleration and masses haven't changed...Determine the accelerations of points A and B on the link and the link's angular acceleration at this instant. EXAM 03. The disk has a mass m = 25kg and is originally spinning at the end of the strut with an angular velocity of ω = 50rad/s. If it is then placed against the wall, for which the coefLicient of...

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Solution for A large sport utility vehicle has a mass of 2.5 * 10^3 kg. Calculate the mass of CO2 emitted into the atmosphere upon accelerating the SUV from 0.0… 3. What is the acceleration of a 10 kg mass pushed by a 5 N force? a = F/m = 5/10 = 0.5 m/sec^2. 4. Given a force of 88 N and an acceleration of 4 m/s2, what is the mass? m = F/a = 88/4 = 22 kg. 5. How much force is required to accelerate a 12 kg mass at 5 m/s2? F = m*a = 12*5 = 60 N. 6. Given a force of 10 N and an acceleration of 5 m/s2, what ...

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Calculating the acceleration due to gravity on the surface of Earth. Mass of Earth is 5.979 * 10 24 kg. Radius of Earth is 6.376 * 10 6 m. Universal Gravitational Constant is 6.67408 * 10 -11 m 3 kg -1 s -2. Step 2: Substitute the values in the formula, g = 6.67408 * 10 -11 (5.979 * 10 24 / (6.376 * 10 6) 2. 3. What is the acceleration of a 10 kg mass pushed by a 5 N force? a = F/m = 5/10 = 0.5 m/sec^2. 4. Given a force of 88 N and an acceleration of 4 m/s2, what is the mass? m = F/a = 88/4 = 22 kg. 5. How much force is required to accelerate a 12 kg mass at 5 m/s2? F = m*a = 12*5 = 60 N. 6. Given a force of 10 N and an acceleration of 5 m/s2, what ...https://StudyForce.com https://Biology-Forums.com Ask questions here: https://Biology-Forums.com/index.php?board=33.0Follow us: Facebook: https://facebo... Proper acceleration, the acceleration of a body relative to a free-fall condition, is measured by an instrument called an accelerometer. In classical mechanics, for a body with constant mass, the (vector) acceleration of the body's center of mass is proportional to the net force vector (i.e. sum of all forces) acting on it (Newton's second law):

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Glencoe The constant of gravity is known to be G = 6.67 x 10-11 m 3 /(s kg) and the mass of the earth is known to be m e = 5.98 x 10 24 kg. The measured period of the moon is 27.3 days (2.3 x 10 6 s). The distance between the moon and the earth can therefore be calculated: r = 3.82 x 10 8 m

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Problem: A 2.0-kg mass and a 3.0-kg mass are attached to a lightweight cord that passes over a frictionless pulley. The hanging masses are free to move. The coordinate systems is with positive direction up for 2.0-kg mass and negative direction down for 3.0-kg mass. Find the acceleration of the smaller mass. Is there any different equation for ...The total mass of the rocket and its full load of fuel is {eq}2.8 \times 10^6 {/eq} kg. The constant force provided by the rocket's motors is {eq}3.2 \times 10^7 {/eq} N. Calculate the vertical ... Jun 19, 2016 · The mass of the Earth is 6 x 10^24 kg and the mass of the Moon is 7.35 x 10^22 kg, and the distance between the two centers is 384,403 km. No. 3. Find the coordinates of the centers of masses of the following (assume the rods are massless):

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A 60 kg block slides along the top of a 100 kg block with an acceleration of 2.0 m/s2 when a horizontal force F of 315 N is applied. The 100 kg block sits on a horizontal frictionless surface, but there is friction between the two blocks.

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1. Mass on a spring. The force exerted by a spring when it is stretched a distance x from its equilibrium position The position, velocity and acceleration of the mass on the spring are given by Does the amplitude drastically effect the period? Find the percent error between the average of the measured...

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A standardized value for acceleration due to gravity was therefore needed. Product of avoirdupois pound and standard gravity Edit The pound-force is the product of one avoirdupois pound ( exactly 0.45359237 kg) and the standard acceleration due to gravity , 9.80665 m/s 2 (32.174049 ft/s 2 ).

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Find its acceleration at each instant time when the velocity is zero. Circular motion Mass point moves moves uniformly in a circle with radius r = 3.4 m Determine the acceleration of the body motion on an inclined plane. Accelerated motion - mechanics The delivery truck with a total weight of 3.6 t...Molar mass and elemental composition calculator. Relative atomic masses are expressed with five significant figures. The molar mass of a substance (M) is the weight of one mole of the substance. The SI unit for molar mass is kg/mol, though the decimal unit g/mol is more commonly used.

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A pilot of mass 70kg pulls out of a dive following a circular path of radius R at a speed of V. If we consider the pilot at the bottom of the dive (the plane is momentarily level), under which condition does the pilot feel the greatest acceleration? (calculate this acceleration) (1) R=1800m, V=125 m/s (2) R=900m, V=125 m/s

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force, the acceleration of any object of mass m will be g, the acceleration of free fall. Importantly, g acts as a proportionality constant, 10 N/kg, which is equivalent to 10 m/s2. Sample Question: How much does a 1-kg bag of nails weigh on Earth? W = mg = (1 kg)(10 m/s 2) = 10 m/s = 10 N, or simply, W = mg = (1 kg)(10 N/kg) = 10 N.

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You and a friend play on a seesaw. Your mass is 90 kg and your friend’s mass is 60 kg. The seesaw board is 3.0 m long and has negligible mass. Where should the pivot be placed so that the seesaw will balance when you sit on the left end and your friend sits on the right end ? the sum of the torques must be zero if the seesaw isn’t to topple On Earth the force of gravity is 10 N/kg. The acceleration due to gravity (how fast things accelerate when you drop them) is approximately 10 m/s 2. What is Weight? Weight is the force of gravity pulling on a mass. Weight is a force, so it is measured in Newtons, not kilograms. weight = mass x gravity. w = m x g. This equation is important!

P57. A block of mass m1 = 3.70 kg on a frictionless plane inclined at angle θ = 30.0 is connected by a cord over a massless, frictionless pulley to a second block of mass m2 = 2.30 kg (Fig. 5-52). What are (a) the magnitude of the acceleration of each block, (b) the direction of the acceleration of the hanging block, and (c) the tension in the ... 3 kg 1 kg 2 kg 4 kg Atwoods 2 • The pulley has a mass of 3.0 kg and a radius of 2.0 cm. • The pulleys mass is concentrated on it perimeter. • Assume the surface is frictionless. • Find the acceleration of the 4.0 kg mass shown. • Find the tensions in the string. 2.5 kg 4.0 kg

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Find the angular acceleration of the sphere when it reaches at the bottom of the incline. Take mass of the sphere is 2 kg and radius of the sphere is 10 cm. If we know the mass of an object in kilograms, and we know the acceleration that an object experiences then we can calculate the force exerted on that object by multiplying the _____ x _____. 1. An unbalanced force of 25 N in an Easterly direction is applied to a 12 kg mass. What will be the acceleration of the mass? 2. Calculate the acceleration of the masses, given that m 1 =3 kg and m 2 = 1. 5 kg. Calculate the magnitude of the tension in the string when the masses are accelerating. 7. In the diagram below, the object placed on the right hand scale pan has a mass M= 25 0 g and it causes both scale pans to accelerate at 2.4 5 ms-2. An empty truck of mass 1000 kg is moving at a speed of 36 km/hr. It is loaded with 500 kg of material on its way and again moves at the same speed. Ans: The acceleration is 10 m/s2. Example - 07: A car of mass 1000 kg is moving at a certain speed when a constant braking force 1000 N acts on it for...

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For a constant mass, force equals mass times acceleration." This is written in mathematical form as F = ma. F is force, m is mass and a is acceleration. Newton's second law says that when a constant force acts on a massive body, it causes it to accelerate, i.e., to change its velocity, at a constant rate.